Prime Factorisation (continues...)

#25

2^4 X 3^5 X 7^2 X 11=2X2X2X2X3X3X3X3X3X7X7X11=2095632

Since the number ends with an even number, it should be divisable by 2.

First,I would divide in by 2. The answer would be 1047816.

2X1047816=2095632

1047816 would be a factor which is greater than 100.

It can also be divided by 4.

4X523908=2095632

It can also be divided by 6.

6X349272=2095632

The final answer-1047816,523908,349272.

#26

2 X 3^2 X 7^3 X 13=80262

3 X 7^2 X 13^3 X 17=5490303

The HCF of this two numbers is 1911.

From the working, I can find out that 7 and 13 are also common factors.

The final answer is-1911,7,13.